This die defines your luck in life, and is rolled by your god of choice at every important event: roll a (0) you fail miserably, (6) you succeed briliantly, (4) you pass, barely.
Would you rather have:
A: a 000666 die?
B: a 111555 die?
C: a 222444 die?
D: a 333333 die?
Option C “222444”.
I coded successes as positive values and failures as negative values. I arbitrarily used a doubling for each greater success/failure level and came up with the following value coding:0 1 2 3 4 5 6 -8 -4 -2 -1 +1 +2 + 4 This results in the following expected values for the offered dice:
A: -2
B: -1
C: -1/2
D: -1All dice are bad, option C is the least bad. And this kinda makes sense. For option A, you may have a fantastic success, but you are also just as likely to complete crash out. And a “crash out” should happen after very few rolls. Option B is a slightly less extreme version of this, but any gains from the 5 results should be more than wiped out by the 1 results. And those should be happening with similar frequency. Option C is again the same thing, but with a slower circling of the drain. 4 results let you recover some, but the 2 wipes out that 4’s benefits and more resulting in a slow decline. And option D is just straight out bad, every result is a failure.
It seems that the only good choice is not to play. ;-)
EDIT: I realized, I made a mistake in my original numbers, I forgot to divide by 6. And this is why coffee should come before math. The conclusions are still the same, but the numbers are different. I’ve corrected those.
A. the 000666 dice.
Failure is capped at rock bottom, whereas the possibilities for success are infinite, so the brilliant success should outweight the miserable failure.
I assume this is the dice for people like Trump. Fail miserably and get convicted in your court case, then get elected president of the united states anyway.